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David Feuer authored
Now that `($)` is representation-polymorphic, `($!)` should surely follow suit. Reviewers: hvr, bgamari, simonpj Reviewed By: bgamari, simonpj Subscribers: simonpj, rwbarton, thomie, carter Differential Revision: https://phabricator.haskell.org/D4382
c9a88db3
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