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Jade
haddock
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5d0a0edc
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5d0a0edc
authored
3 years ago
by
Hécate Moonlight
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remove Bug873
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b07b5ab2
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hoogle-test/ref/Bug873/test.txt
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hoogle-test/ref/Bug873/test.txt
hoogle-test/src/Bug873/Bug873.hs
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hoogle-test/src/Bug873/Bug873.hs
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hoogle-test/ref/Bug873/test.txt
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-- Hoogle documentation, generated by Haddock
-- See Hoogle, http://www.haskell.org/hoogle/
@package test
@version 0.0.0
module Bug873
-- | Application operator. This operator is redundant, since ordinary
-- application <tt>(f x)</tt> means the same as <tt>(f <a>$</a> x)</tt>.
-- However, <a>$</a> has low, right-associative binding precedence, so it
-- sometimes allows parentheses to be omitted; for example:
--
-- <pre>
-- f $ g $ h x = f (g (h x))
-- </pre>
--
-- It is also useful in higher-order situations, such as <tt><a>map</a>
-- (<a>$</a> 0) xs</tt>, or <tt><a>zipWith</a> (<a>$</a>) fs xs</tt>.
--
-- Note that <tt>(<a>$</a>)</tt> is levity-polymorphic in its result
-- type, so that <tt>foo <a>$</a> True</tt> where <tt>foo :: Bool ->
-- Int#</tt> is well-typed.
($) :: forall (r :: RuntimeRep) a (b :: TYPE r). (a -> b) -> a -> b
infixr 0 $
($$) :: (a -> b) -> a -> b
infixr 0 $$
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hoogle-test/src/Bug873/Bug873.hs
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{-# LANGUAGE Haskell2010 #-}
module
Bug873
((
$
),
(
$$
))
where
infixr
0
$$
(
$$
)
::
(
a
->
b
)
->
a
->
b
f
$$
x
=
f
x
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