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Ian Lynagh authored
I don't think it was causing any problems, but TimeToUS(x+y) would have evaluated to x + (y / 1000)Ian Lynagh authoredI don't think it was causing any problems, but TimeToUS(x+y) would have evaluated to x + (y / 1000)
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I don't think it was causing any problems, but
TimeToUS(x+y)
would have evaluated to
x + (y / 1000)
I don't think it was causing any problems, but
TimeToUS(x+y)
would have evaluated to
x + (y / 1000)